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why Nuclear Physics cannot be entirelly correct

I can answer this, Tubbythin:
:p
pedrone,
why did you not know that the standard way to have hyperlinks is with the text as in neutron (stability and beta decay)?


:D
Wow !!! :D
:D
This is beta decay of neutron:
Internal bremsstrahlung spectra from S35 and Pm147 have been investigated with the NaI scintillation spectrometer

pedrone,
dont you know there is no difference between the beta decay of a free neutron and the beta decay of a neutron in a nuclei ? (as S35 and Pm147)
:D

pedrone,
I suspect that you're acting ignorant on purpose
:mad:

By hiding the link a bit, Tubbythin was trying to not embarass you. Pity that you insisted in doing it for yourself!

Reality Check
your ignorance is terrible.

I actually am amazing by your tallent to say foolishes.

Beta decay is a phenonenon in which electrons (or positrons) are emittted.

The electrons can be emitted by a nucleus (as for instance the S35). So, it is the beta decay of the nucleus S35.
After the decay, the free electron is decelerated by the sulfur nucleus.


One electron can also be emitted by a free neutron: n-> p+e+v
This is named beta decay of neutron.
In this case, the free electron must be decelerated by a proton.
But we dont have experimental data proving that it occurs


So, that link posted by Tubbythin is NOT beta decay of neutron, it is the beta decay of S35
:)
 
Reality Check
your ignorance is terrible.
pedrone, your ignorance is terrible: beta decay is the decay of a neutron whether free or inside a nucleus.
neutron (stability and beta decay)
Free neutrons decay by emission of an electron and an electron antineutrino to become a proton, a process known as beta decay
n → p + e + ν

Neutrons in unstable nuclei can also decay in this manner.

Beta Decay
In β− decay, the weak interaction converts a neutron (n) into a proton (p) while emitting an electron (e−) and an electron antineutrino (νe):
dc2c5ef257da973150e3aafd994787fe.png

So, that link posted by Tubbythin is THE BETA DECAY OF A NEUTRON IN A NUCLEUS, it is the beta decay of of a neutron in the nucleus of S35.​

 
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Trepidation can also mean a shivering, tremulous (trembling) motion....of the body, as an emotional response.
It does not, afaik, refer to motion of things.

Finding (by Pedrone) interesting sounding words is one thing, understanding them is something else.
Pedrone appears to be very lax in his thinking- and judgement skills.

Daylightstar,
do you really believe that Tubbythin did not notice it?

Of course he understood very well what I meant to say.

But he simulated he did not understand.
It's a smart strategy used by those ones that have not a satisfactory argument to reply their opponent, and so they imitate a person with disability of reasoning
:D
It's a very smart strategy... nobody perceives it... :p
 
Of course he understood very well what I meant to say.
pedrone - you are wrong. No one undererstands what you mean by trepidation because that term does not exist in modern physcs.

The word trepidation refers to the feelings of a person.

We know that English is your second language so your mistake is understandable. But you need to find the correct term.
 
pedrone, your ignorance is terrible: beta decay is the decay of a neutron whether free or inside a nucleus.
neutron (stability and beta decay)


Beta Decay


So, that link posted by Tubbythin is THE BETA DECAY OF A NEUTRON IN A NUCLEUS, it is the beta decay of of a neutron in the nucleus of S35.​


:)
Oh, God, he did not understand yet.

Reality Check, look the difference:

- In the beta decay of the nucleus S35, the free electron is decelerated by the sulfur nucleus.


- In the beta decay of neutron, the free electron must be decelerated by a proton.
But we dont have experimental data proving that there is deceleration and Bremsstrahlung occurs in this case.


If you do not understand it yet, the people here will laugh of you
:D
 
:p
Tubbythin,
why did you hide the link you posted with that "Err..." ?

He didn't hide it! Apparently you didn't read my long post of advice to you! UNDERLINED WORDS ARE SUPPOSED TO BE LINKS!

You are NOT to underline words just because you feel like it, or it looks pretty! Underline is SUPPOSED to be reserved for links only! I already explained this earlier in a another post.

You seriously need to read everything as thoroughly as possible when someone takes time out of their life to give you much-needed advice. I wasn't even ridiculing you whatsoever in that post, and I was quite civil.

I suggest you go back, and read most of my longer posts over again.
 
pedrone - you are wrong. No one undererstands what you mean by trepidation because that term does not exist in modern physcs.

The word trepidation refers to the feelings of a person.

We know that English is your second language so your mistake is understandable. But you need to find the correct term.
:(
I suppose I'm not discussing with idiots

Besides, as English is your first language, it's easier to you to understand what I write (because as it is your first language, you have the duty to know the several different applications of a word in differente situations).
And since we're not speaking about love, but about bodies gyrating with unbalanced masses, then there is no need to be a genius to realize what I'm speaking of.

Unlike, to me is not so easy, because the Google translator do not tell me in what situations a word must be used.
 
:(
I suppose I'm not discussing with idiots
That is correct - you are not discussing with idiots. You are discussing with English speaking people who know a lot more physics than you seem to display (e.g. the rather dumb cartoons you have been using).

If you want to be understood you need to either use the correct terms, describe what your term means (so that we can tell you the correct term) or cite the definition of the term.

What is "trepidation", pedrone.
 
He didn't hide it! Apparently you didn't read my long post of advice to you! UNDERLINED WORDS ARE SUPPOSED TO BE LINKS!

You are NOT to underline words just because you feel like it, or it looks pretty! Underline is SUPPOSED to be reserved for links only! I already explained this earlier in a another post.

You seriously need to read everything as thoroughly as possible when someone takes time out of their life to give you much-needed advice. I wasn't even ridiculing you whatsoever in that post, and I was quite civil.

I suggest you go back, and read most of my longer posts over again.
Nihilianth,
when I want to call the attention of somebody to a link, I dont hide the link.
Unlike, I put it in evidence.
After all, as the link reinforces my argument, why a hell would I hide it, with a small word as "Err..." ?
 
That is correct - you are not discussing with idiots. You are discussing with English speaking people who know a lot more physics than you seem to display (e.g. the rather dumb cartoons you have been using).

If you want to be understood you need to either use the correct terms, describe what your term means (so that we can tell you the correct term) or cite the definition of the term.

What is "trepidation", pedrone.
:D
trepidation is what I feel for the people here...
 
Nihilianth

I suspect that some people here say foolishes purposely, so that to irritate their opposers.

By this way the opposer gets angry, he calls the other "idiot", and then he is banned.

What do you think ?
 
:)
Oh, God, he did not understand yet.

Reality Check, look the difference:

- In the beta decay of the nucleus S35, the free electron is decelerated by the sulfur nucleus.


- In the beta decay of neutron, the free electron must be decelerated by a proton.
But we dont have experimental data proving that there is deceleration and Bremsstrahlung occurs in this case.


If you do not understand it yet, the people here will laugh of you
:D
:)
Oh, God, he did not understand yet.

pedrone, you went on about a difference between free electron decay and beta decay in a nucleus.
There is none.

There is a difference between the external Bremsstrahlung that the electron produces
  • In the beta decay of the nucleus S35, the free electron is decelerated by the sulfur nucleus.
    Bremsstrahlung radiation has been detected in this process .
  • In the beta decay of a free neutron, the free electron is be decelerated by the proton.
The process is exactly the same. The only difference is the source of the electromagnetic field that decelerated the electron and produces the radiation.

I do not have access to this paper but notice its Google summary:
Fundamental physics with slow neutrons by K Schreckenbach - 1994
This includes the bremsstrahlung spectrum in the free neutron decay and ... ground neutron beam would be necessary, such as cold neutrons emerging from a neutron guide. ... be an asymmetry measurement relative to the neutron spin. ...

We do have experimental data showing that there is deceleration and Bremsstrahlung occurs in this case.
 
:D
trepidation is what I feel for the people here...
So you have no idea what you mean by "trepidation".
That makes your original post about it even more idiotic (the cartoons were the first signs of ignorance, thanks for confirming that the post was totally dumb :eye-poppi).
 
:)
Oh, God, he did not understand yet.

Reality Check, look the difference:

- In the beta decay of the nucleus S35, the free electron is decelerated by the sulfur nucleus.


- In the beta decay of neutron, the free electron must be decelerated by a proton.
But we dont have experimental data proving that there is deceleration and Bremsstrahlung occurs in this case.


If you do not understand it yet, the people here will laugh of you
:D

Do you read what the real scientists are posting here? You ignore everything they say and come back with more misinformed twaddle. Trepidation is not a term used in physics. Where did you study and what are your qualifications?
 
Nihilianth

I suspect that some people here say foolishes purposely, so that to irritate their opposers.

By this way the opposer gets angry, he calls the other "idiot", and then he is banned.

What do you think ?

Thinking is good,you ought to try it sometime.
 
:)

I do not have access to this paper but notice its Google summary:
Fundamental physics with slow neutrons by K Schreckenbach - 1994

Quote:
This includes the bremsstrahlung spectrum in the free neutron decay and ... ground neutron beam would be necessary, such as cold neutrons emerging from a neutron guide. ... be an asymmetry measurement relative to the neutron spin. ...


We do have experimental data showing that there is deceleration and Bremsstrahlung occurs in this case.

:confused:



There are several effects in the decay of the neutron which have not been studied. This includes the bremsstrahlung spectrum in the free neutron decay and ...
http://www.google.com.br/#hl=pt-BR&...decay+&aq=f&aqi=&aql=&oq=&fp=286cf708affef362
:D:D:D


Abstract
The theory of quantum electrodynamics (QED) predicts that beta decay of the neutron into a proton, electron and antineutrino should be accompanied by a continuous spectrum of soft photons. While this inner bremsstrahlung branch has been previously measured in nuclear beta and electron capture decay, it has never been observed in free neutron decay
http://www.ncbi.nlm.nih.gov/pubmed/17183320
:D:D:D
 
:confused:
There are several effects in the decay of the neutron which have not been studied. This includes the bremsstrahlung spectrum in the free neutron decay and ...
http://www.google.com.br/#hl=pt-BR&...decay+&aq=f&aqi=&aql=&oq=&fp=286cf708affef362
:D:D:D
You are right. My search terms missed out the first sentence so in 1994 there are several effects in the decay of the neutron which have not been studied. This includes the bremsstrahlung spectrum in the free neutron decay and ...
(or maybe the first sentence only appears ion the Portuguese version!)

:confused:
Abstract
The theory of quantum electrodynamics (QED) predicts that beta decay of the neutron into a proton, electron and antineutrino should be accompanied by a continuous spectrum of soft photons. While this inner bremsstrahlung branch has been previously measured in nuclear beta and electron capture decay, it has never been observed in free neutron decay
http://www.ncbi.nlm.nih.gov/pubmed/17183320
:D:D:D
You are wrong:
Observation of the radiative decay mode of the free neutron
The theory of quantum electrodynamics (QED) predicts that beta decay of the neutron into a proton, electron and antineutrino should be accompanied by a continuous spectrum of soft photons. While this inner bremsstrahlung branch has been previously measured in nuclear beta and electron capture decay, it has never been observed in free neutron decay
inner bremsstrahlung branch of the decay = n -> p + e + v + photon, this has been observed

:D:D:D
 
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:confused:



There are several effects in the decay of the neutron which have not been studied. This includes the bremsstrahlung spectrum in the free neutron decay and ...
http://www.google.com.br/#hl=pt-BR&...decay+&aq=f&aqi=&aql=&oq=&fp=286cf708affef362
:D:D:D


Abstract
The theory of quantum electrodynamics (QED) predicts that beta decay of the neutron into a proton, electron and antineutrino should be accompanied by a continuous spectrum of soft photons. While this inner bremsstrahlung branch has been previously measured in nuclear beta and electron capture decay, it has never been observed in free neutron decay
http://www.ncbi.nlm.nih.gov/pubmed/17183320
:D:D:D


Couldn't control yourself and you finally gave in to the desire to overuse smileys and colorful text formating, huh?

Why do you think they make your silly posts any more convincing?
 
Couldn't control yourself and you finally gave in to the desire to overuse smileys and colorful text formating, huh?

Why do you think they make your silly posts any more convincing?

I've never understood why the delusionauts do that. My theory is that they are not allowed anything sharp where they live,so they are used to writing with a box of crayons.
 

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