Doesn't the gamma function change some aspects of the nature of physics as one moves (rotates?) from space dimensions to time?
The gamma factor is actually just the cosine of the angle between two velocity (four-)vectors, e.g., the observer's and some particle's, except the angle is imaginary, or equivalently, the trigonometry is hyperbolic.
Ordinary inner product: <u,v> = ║u║║v║ cos θ
Hyperbolic inner product: <u,v> = ║u║║v║ cosh α, γ = cosh α.
So rather than breaking anything, the gamma factor an integral part of the the rotation. Take a gander at the Lorentz transformation in terms of the angle (rapidity) α = atanh(v) = acosh(γ):
Code:
[t'] = [ γ -γv ][t] = [ cosh α -sinh α ][t] <--> [x'] = [cos θ -sin θ][x]
[x'] = [-γv γ ][x] = [-sinh α cosh α ][x] <--> [y'] = [sin θ cos θ][y]
This is a straightforward analogue of Euclidean rotations. Formally, the correspondence is a rotation in the complex plane: {t = iy, α = iθ}.
You can define that as an effective theory - but if your fundamental theory is Lorentz invariant, non-locality will always imply acausality.
Given a scalar field t as previously described, say one has a four-acceleration of a particle at x orthogonal to its four-velocity, <a,u> = 0, given by:
[latex]a \propto \int\frac{t_{,\alpha}t_{,\beta}T^{\alpha\beta}(x')}{||x-x'||^3}\left[(x-x') - u\langle u,x-x'\rangle\right]\;{\mathrm d}^3x'[/latex]
with the domain of integration a slice of constant t. The density ρ = t
,αt
,βT
αβ is Lorentz-invariant, as is the domain and vector lengths, since they are determined geometrically. Since orthogonality is also a geometric, coordinate-invariant condition, I don't see how this acceleration would not be Lorentz-invariant.
I guess that depends on what you mean by "spacetime structure". I had in mind that the spacetime is locally Minkowski, and that the fundamental laws of physics are Lorentz invariant. I think that's what you need for my statement to hold.
I don't see what's wrong with the above, so I guess I'm confused about the statement "the fundamental laws of physics are Lorentz invariant." ... Come to think of it, I might be conflating:
(1) Lorentz-invariance of laws ~ "an isolated experiment gives the same result in every inertial frame."
(2) Lorentz-invariance of laws ~ "physical quantities given by laws are Lorentz-invariant."
The Newtonian gravity example seems to follow the latter but not the former.
(I apologize if that's the kind of thing that's obvious to physicists, but I honestly didn't realize that those two are inequivalent until now. Or is there anything else I'm missing?)