Merged Theory links Newtonian/Quantum the amazing Frank Znidarsic

[JCM]

How would one measure a sound wave traveling through a neutron or proton? How would it arrive? How would it leave?

Actually my mistake as I said I am not Frank I may be getting this all completely wrong.
I know it has to do with impedance matching and sound wave propagation but it must relate to the electrons not the nucleus. It has to do with the quantum transition and a measurement of the sound wave propagation during which somehow gets the 1.094 MHz m. Or that might all be totally wrong

 

[ben m]

I want concrete examples using math dissecting the work entirely not a simple skim of the premise. If its wrong ok but dont just tell me show me in his work in his equations.

I did already. The wavelength of a photon, times its frequency, is 2.99 x 10^8 m/s, not 1.094 x 10^6. Therefore your equation

1.094 x 10^6 = f lambda

is wrong.

 

[Soapy Sam]

How would one measure a sound wave traveling through a neutron or proton? How would it arrive? How would it leave?

How would it fit?

 

[JCM]

I did already. The wavelength of a photon, times its frequency, is 2.99 x 10^8 m/s, not 1.094 x 10^6. Therefore your equation

1.094 x 10^6 = f lambda

is wrong.

The wavelength of a photon during transition times the frequency of an emitted photon
more simply

how many times the emitted photon is oscillating between its electrostatic and magnetic fields per second multiplied by how far the oscillation goes each time aka the distance traveled each time it oscillates

Maybe misinterpreting the equation? Did you get to watch the video of the math?
Here it starts at the exact spot and is only a couple minutes
http://www.youtube.com/watch?v=ahRJW6JViQ0&feature=player_detailpage#t=81s

 

[JCM]

How would one measure a sound wave traveling through a neutron or proton? How would it arrive? How would it leave?

Actually my mistake as I said I am not Frank I may be getting this all completely wrong.
I know it has to do with impedance matching and sound wave propagation but it must relate to the electrons not the nucleus. It has to do with the quantum transition and a measurement of the sound wave propagation during which somehow gets the 1.094 MHz m. Or that might all be totally wrong

How would it fit?

Optical Phonons
Actually I was right the velocity of sound within the nucleus is 1.094 x 10^6 m/s

 

[MattusMaximus]

But 'sound waves propagation within the nucleus', that is nonsense. Surely you have garbled something or it is nonsense.

I noticed that as well. I think this stuff on Znidarsic's part came from the same orifice from which he pulled the apparent connection to Bose-Einstein Condensates.

 

[MattusMaximus]

Optical Phonons
Actually I was right the velocity of sound within the nucleus is 1.094 x 10^6 m/s

"Optical phonons"?

*facepalm*

Dude, we call those photons if in the electron cloud... if it's within the nucleus it is gluons.

 

[Tubbythin]

But 'sound waves propagation within the nucleus', that is nonsense. Surely you have garbled something or it is nonsense.

Well "people" certainly talk about sound speed in relation to nuclear incompressibility with "giant resonances". Not that I'm saying this guy isn't talking nonsense.

 

[JCM]

Dude, we call those photons if in the electron cloud... if it's within the nucleus it is gluons.

what is the mechanical equivalent of a gluon?

 

[ben m]

The wavelength of a photon during transition times the frequency of an emitted photon

The "video of the math" is the same as what you posted before, just presented in the slowest and most annoying format possible.

My answer remains the same. The only wavelength you will find associated with a photon is the one I mentioned already. From what observation do you obtain something different? Or are you guessing that the rest of the calculation "must be" right, and using a nonsense-wavelength as the free parameter to make the numbers add up?

 

[ben m]

Well "people" certainly talk about sound speed in relation to nuclear incompressibility with "giant resonances". Not that I'm saying this guy isn't talking nonsense.

... and that sound speed is much faster than 10^6 m/s. It's something like 3x10^7 m/s.

 

[JCM]

The only wavelength you will find associated with a photon is the one I mentioned already. From what observation do you obtain something different? Or are you guessing that the rest of the calculation "must be" right, and using a nonsense-wavelength as the free parameter to make the numbers add up?

I doubt the math is using a made up wavelength but i'll try to find out how it was derived and then post.

 

[JCM]

How would one measure a sound wave traveling through a neutron or proton? How would it arrive? How would it leave?

He's saying as a very simple model where you have nucleons acting as marbles and looking at the forces in between them like phonons where the electrical force balances the nuclear force in an atomic structure you have positive charges balancing the negatives structure and you get the propagation of waves using that analysis he derived the velocity of sound within the nucleus and the solution is independent of the number of neutrons

The quantum condition is a classical effect of a condition where the velocity of light equals the velocity of sound. The velocity is that of the transitional quantum state.

The velocity of sound, which is normally associated with heavy nucleons, it's a mechanical property, equals the propagations in the electron environment, which is usually associated with the velocity of light. The velocity of sound during the quantum transition equals the velocity of light all the waves propagate at the same velocity. If the magnitude of the forces are equal is the only we can get the same velocity considering the mass is fixed
The quantization of energy is determined of points of electromagnetic and gravitomagnetic accessibility that is the point where all the waves equal that is much more than mechanical and electrical waves being equal it says under that condition its a dielectric condition that the strength of the natural forces is equal and the range is equal

 

[Dancing David]

I am speaking of nucleons

there isn't going to be an effect in the nucleons or nucleus during the phase transition of an electron from one shell to another, so either you have garbled something or it is nonsense.

 

[Dancing David]

Well "people" certainly talk about sound speed in relation to nuclear incompressibility with "giant resonances". Not that I'm saying this guy isn't talking nonsense.

Compression that makes sense, phase transitions in the electron cloud I am not sure of. feel free to correct me.

 

[JCM]

so either you have garbled something

yes that is the case see my latest post

 

[JCM]

it's the speed of light. By definition. It's not 1.094x10^6 m/s, it's 3x10^8 m/s.

The speed of light in a B.E.C. is adjustable down to nothing thats why the elastic constant is actually variable but there are points of energetic accessibility where the frequency of the nuclear state equals an integer multiple of the frequency of the electronic state and from that Frank pulled out the structure of the hydrogen atom

 

[ben m]

The speed of light in a B.E.C. is adjustable down to nothing thats why the elastic constant is actually variable but there are points of energetic accessibility where the frequency of the nuclear state equals an integer multiple of the frequency of the electronic state and from that Frank pulled out the structure of the hydrogen atom

Unintelligible gibberish.

I repeat the question: what "transition wavelength" data do you think agrees with the statement that lambda * f = 1.094x10^6 m/s?

 

[JCM]

Frank's classical radius of the electron shows that the fields of matter are pinned into the structure of matter at that classical radius of the electron like you pin fields in to a superconductor by adding discontinuities. With that model you get the phase velocity equals the velocity the phase velocity equals the velocity of light the group velocity equals the movement of the structure and all of special relativity emerging under that condition
Looking at the Compton frequency, the De broglie wave being the Doppler shifted reflected Compton frequency emerges naturally from this model out of that condition

 

[JCM]

Unintelligible gibberish.

True or not?

The speed of light in a B.E.C. is adjustable down