Zig's question was not a crackpot question. It was about as reasonable as humanly possible.
The fact that you can't treat it as such speaks pretty badly of your chances of ever communicating your ideas. You seem to assume that Zig (and I, and everyone) comes into this conversation understanding your model perfectly, and that your model is obviously correct at first glance. Given this (you seem to think) the only reason we could possibly even ask for clarification is that we're "crackpots".
I have not been the first to call people "crackpots" on this forum; but since it is totally OK for people who post on this forum to call me a crackpot, I decided to retaliate consistently with the same term when they raise crackpot ideas which are not physically possible
Have you ever taught a class? Have you ever given a seminar? I'd hate to see the question-and-answer period. "Dr. Prins, I was unable to read the y-axis on slide 3, can you go back?." "Dr. Prins, you spoke only about DC current and I wanted to ask about AC." You stupid crackpots, only stupid BCS-worshippers could ask such crackpot questions, etc.
Do you see how insulting you are by jumping to a conclusion on my character after I was first classified on this forum as being a crackpot. Although I have never reacted in the way you are so viciously assuming that I will, I might do so when a person stands up in a seminar and states that what I am saying is contrary to main stream dogma and therefore
I must be a crackpot. I do not mind to respond to civil questions but what has happened in my life during the past ten years, and also now in this forum, was that people assume that I must be crackpot until I can prove that I am not one. Even a murderer in court is treated more civilly.
"any credence."? You'd have to be a crackpot not to. Not giving it credence means that you're happily assuming that everyone involved, over 60+ years, has been a blinker-wearing moron.
I do not have to assume it, the physics involved in the BCS model is based on crackpot ideas and it is easy to prove to people with open minds; but not to people who find me guilty of being a crackpot before they are willing to try and understand what I am saying: I have explained in detail in a book why it is crackpot, and to expect that I can summarize a detailed analyis on a thread in a discussion forum, without posting the contents of the book, is impossible. If you want the full details I suggest that you buy the book.
Before I was willing to state that BCS is crackpot, I spent months analyzing every aspect of it in detail; and did not allow myself to be swayed by the crackpot argument that if the main players in the field have not picked up that it is crackpot for over 60 years, it cannot be crackpot. Physics must not be decided by majority vote but by facts and, to follow the facts, you must understand physics; instead of praying at the feet of Bardeen, Schrieffer and Cooper. And you should have a knowledge that is deep enough to understand the difference between a gravity field and an electric field: Your next sentence demonstrates that you are not able to understand the latter. And I am stating this
NOT to insult you, but just as a fact.
Outside of my field, but: It sounds to me like you're double-counting a voltage drop---as though you were calculating the kinetic energy of a falling hammer and saying, "Well, there's +mgh (!) from the change in gravitational potential, and also +1/2mv^2 = mgh because the kinetic energy increases, so the hammer has 2mgh when it hits the ground". If I'm wrong, explain (and link to a source).)
As you requested I will try and do it slowly and in detail: It is not the same as just dropping a hammer when a charge-carrier moves through a Josephson junction. When you drop a hammer it starts off with ZERO kinetic energy and therefore the kinetic energy which it has to dissipate when reaching the ground, is equal to the potential energy before you dropped it: i.e. the position of your hand above the floor when you drop the hammer.
But if you first throw the hammer into the air and then miss catching it, the kinetic energy with which it reaches the ground is equal to the potential energy it had when it turned around in the air to fall towards the floor; and if the potential energy between the position of your hand and the position in the air, at which the hammer turns around to drop to the floor, is the same as the difference in potential energy between your hand and the floor, then the kinetic energy which has to be dissipated is TWICE the kinetic energy that will dissipate when just dropping the hammer: IS IT NOT??
Now let us return to the Josephson junction: when the charge carrier is on the higher energy side it has a potential energy qV relative to the energy on the other side, Thus, as I have clearly argued, if you can move the charge-carrier to the other side WITHOUT changing its energy and release it, it will radiate energy qV. BUT in order for the charge-carrier to move to the other side it has to move
through the junction within which it encounters a voltage V; and it is then accelerated by the voltage in the junction to, IN ADDITION, gain kinetic energy qV. This is the same as throwing the hammer into the air. Thus it now has a total energy of 2qV to dissipate.
Experimental measurements show that the energy being dissipated per charge-carrier is 2eV: THUS q
MUST BE e AND
THEREFORE THE CHARGE CARRIERS MUST BE SINGLY CHARGED. Cooper pairs, which is at the heart of BCS, is thus a crackpot concept and therefore BCS is crackpot. There are also other reasons why the traditional theories on superconduction are crackpot. They are all summarized in my book.