The heating mechanism is not a "mystery", it's called "electricity" and "coronal loops". It's only a mystery to you guys because you *refuse* to consider the one logical method to explain it due to your extreme and irrational prejudice against anything and everything related to EU theory.
How much current is involved, Michael? What's the voltage difference along these loops? What creates those voltage differences? What's the resistance of the loops?
You can only explain this with electricity if you can put numbers to it. And you can't. So what you have is not an explanation, it's the beginning of a
guess, Michael.
True, and every plasma layer can do that because of the discharge between the surface and the heliosphere, and because each layer is covered by lighter layers.
Nope. The photosphere is (by definition) opaque, so nothing under it can radiatively couple to anything outside it. Basic thermodynamics fail, Michael.
Oh, and once again, you can't get
discharges in a plasma, because plasmas (yes, even your "dusty" plasmas) do not experience dielectric breakdown. Because they are
already conducting.
That seems to be the magic SPF infinity claim you have never bothered to demonstrate.
Oh, but I have. First off, the photosphere is
by definition the outer opaque layer of the sun. So saying it's opaque is really a tautology. The only way it wouldn't be is if it's
not really a photosphere at all.
But it doesn't matter, because there is
observably a mostly opaque layer. Blackbody radiation, Michael. Thermodynamics REQUIRES that a source of blackbody radiation MUST be opaque. And we can see a 5700 K source of blackbody radiation around the sun. You can make whatever claims you want to about the composition of this blackbody source, but it just doesn't matter: it's hot, and it's opaque. You don't need to know ANYTHING about the sun to conclude that. Any conclusion other than that is a violation of the 2nd law of thermodynamics, and is equivalent to a perpetual motion machine. Do you believe in perpetual motion machines, Michael?
All the satellite images show all kinds of stuff below the photosphere in images of a sunspot.
Yeah... not so much.
All the iron ion wavelengths penetrate the photosphere and even x-rays seem to be visible below the photosphere in that Hinode image you folks keep ignoring.
Nope. And it doesn't matter anyways. Since the layer underneath the photosphere is colder in your model, transparency to x-rays or even far UV is
irrelevant. Your solid layer cannot lose heat through x-ray radiation because it's too cold to radiate enough x-rays and far UV. Again, simple thermodynamics, and you fail to grasp it.
Your whole argument seems to hinge on your false belief that the photosphere is "opaque" to every single wavelength of light
No, Michael. It hinges on the belief (confirmed by
measurements of the blackbody spectra) that the photosphere is mostly opaque to IR, visible, and UV radiation. That's all it needs, because those are the only wavelengths that anything at or below the temperature of the photosphere can radiate any appreciable amount of energy at. You'd know this if you understood thermodynamics.