Hm - a 33 000 tons ship at 5 m/s (10 knots) horzontal speed at collision has evidently more (2.78 times!) KE than an upper block of WTC 1 (also 33 000 tons) but only contacting vertcally the lower structure at 3 m/s.
The contact area is also very different. The ship's bow is pointed, the upper block is a 4000 m² floor flat. Assuming uniform density of the upper block and uniform impact over 4000m² the impact pressure is pretty low. The peak pressure is time dependent but remember - the columns only occupy 0.13% of the floor area. The rest is the upper floor of the lower structure that is subject to the pressure. Actually the same pressure is applied to the lowest floor of the upper block.
The ship collision may stop after a penetration of 5-10 meters into the other ship (of same size). The pointed bow of the striking ship really breaks the side of the stricken ship but after a while (even if the driving force of the striking ship is still on) the destruction is arrested.
Why the upper block of WTC 1 would cause the lower structure to collapse is beyond me. See .
I would expect that only the columns of the upper block and the lower structure would slice the floors apart of respective parts and that the floors would get entangled as seen in the right figure of the link above. Two walls of the upper block may then have sheared off and fallen to the ground. The rest of the upper block remains in the top of the lower structure. The lower structure would still stand. Quite basic actually.
So pls re-do your energy calculations using my observations.
Kind regards
Heiwa
In case I missed something in the preceeding gagillion pages of babble, I must speak out on this, sorry if this is old territory but...
The ship travelling at 10 knots begins to decelerate I.E. slow down.
The top floors of the WTC are undergoing a constant accelleration of 10 meters per second, per second, thereabouts (more like 9.8...ish)...
Lets get simple and look at what happens when the upper structure first falls, and hits the floor below:
The top floors starts with a downward velocity of 0.
It falls.
It accellerates.
It reaches (by your calculations) 3 m/s.
33,000 tons (your figure)
= 3,300,000 kg * 3ms-1 = 9,900,900 kgms-1 of momentum
Which strikes the floor below the falling section.
OK. So what happens now? Obviously, the upward part will slow down, maybe break up a little, but the floor beneath will most probably (and in fact did) give way due to the inability of the load bearing beams to support the incredible forces on top of it.
So what is the status of the system now? Well, if (as was the case) the top floors did not reach a speed of 0 (i.e. they were still moving downwards, even just a little bit), then we can repeat the steps for the next floor, only now the starting velocity is greater than 0, and the mass of the upper section includes the structure of the floor that just got crushed. This gives the falling debris even more power to punch through the next floor, as it will be moving faster and have more weight.
Also some other stuff you mentioned, the columns are likely welded or bolted together or a combination of both, as such they will have weak spots at the joins which when a gagillion tons of building is dragging them down and inwards will cause them to snap, not tangle up like some kind of gargantuan ball of wool...
But then that is just my thoughts I am no expert at all in anything.