Thanks for the peep review:
1. The photo of WTC2 shows the upper block inclined outside the lower structure and, logically, cannot drop on the lower structure (it will contine to incline and slide off). In fact it disappears completely soon after.
No it doesn't. How hard can it be to use your own eyes when looking at a picture? The upper block has ROTATED, and it cannot slide. For an object to be able to slide off the surface of another, both surfaces must be capable of resisting a force that will move the upper block over. Homogeneous objects can do this (tree trunks, bales of wool). Steel structures cannot. The upper block physically can't slide off the lower block.
2. The upper block is supposed to be rigid and intact. It is not supposed to be damage before initiation. My point is that the upper block of WTC1 disintegrates 3-4 seconds before initiation, which is not explained.
The upper block is NOT supposed to be rigid and intact. It is modeled that way by people like Bazant to make the MATH EASIER. Do you understand this concept, yes or no? That's a direct question, I expect an answer. Furthermore, how can the upper block disintegrate before the collapse even starts? Do you even read what you write?
3. The upper block of WTC1 is not NEAR free falling on the lower structure below the initiation zone. It telescopes into itself, while the structure in the initiation zone is intact! Just look at the bottom of the upper block - floor 97.
I would say, "no it's not" again. But that doesn't have the same affect as me saying, "prove it". You say the lower structure is intact. You can't see this because it's obscured by smoke. Logic suggests that damage done to the upper block must also correspond damage to the lower block.
4. No, the static stresses in the load bearing columns prior collapse are >20% yield in the walls and <30% yield in the core. Calculations are given in the paper.
Complete B.S. Again, you do not provide calculations in your paper. This is your "calculation":
heiwa-paper said:
The mass above the core is only13 200 tons supported by the 47 core columns with total area 2.1 m². On average each core column carries abt 280 tons so the average compression is 629 kgs/cm² or 63 MPa or 25% of yield
THIS IS NOT AN ACCEPTABLE MANNER IN WHICH TO CALCULATE INDIVIDUAL STRESSES IN THE COLUMNS. It ignores individual columns being overloaded, it ignores columns being stressed laterally by the structure redistributed vertical forces.
heiwa said:
5. Still, the floor is not a primary load bearing part. Clear from the article. It only transmit a load on the floor to the column. Remove all floors and no loads are transmitted to the columns, the latter then only being stressed by their own weight <3% of yield. Buckling is then prevented by the spandrels/beams and the other walls. Service floors are different with strong beams connecting perimeter/core.
Again, complete ********. The spandrels cannot brace the columns in the out-of-plane direction. This is simple engineering mechanics. Please explain to me how a 5/8" over the course of 208ft is going to brace a column against buckling.
heiwa said:
6. The columns of the upper block are interconnected with spandrels/beams at every floor that will transmit the load on the cut column to the other columns. Remember that 38 wall columns were cut 100+ minutes earlier and nothing happened.
Then why do you not include the effect of this in your calculations? I have, I found that the columns being cut alone wouldn't cause collapse, but if the other columns nearby where then heated above 600c that they would fail. Why can't you do this? Are p-delta calculations too difficult, or are you afraid of the result?
heiwa said:
7. For an upper block to free fall vertically and impact all columns of the structure below simultaneously, evidently all the remaining supports must be removed at the same time. If the upper block tilts or gets inclined because the supports do not fail simultaneusly, the impact cross area of the upper block is also inclined = no instantaeous impact! Compare 1 above.
No, the columns do not fail at the same time. There is a chain reaction from one wall failing due to p-delta affects causing large stress redistribution to the other remaining columns which in turn get pulled over. The fact that these do no fail simultaneously is shown BY HOW THE TOWER ROTATES. THIS HAS ALREADY BEEN EXPLAINED, STOP WITH THE STRAWMAN.
heiwa said:
8. I know the upper block was not lowered. It collapsed into itself before it started the move down into the initiation zone.
How the frick can something collapse into itself before it moves down?
heiwa said:
9. Reference link is British authorities. At 500°C only yield stress is reduced, say 20%.
A picture is worth a thousand words
I have to wonder why you didn't say 600°C That's more than a 50% reduction. And then of course, there is the modulus of elasticity decreases, which are significant from a p-delta perspective.
And then in your paper, your say:
heiwapaper said:
How is the yield stress of steel affected by heat? In this writer's opinion it is not affected very much at about 500°C. This is confirmed by any fire test - the test chamber and what's in it never collapses due to the heat inside up to 1000°C. The heat inside is normally by kerosene set on fire.
Why do you mention 1000°C tests without mentioning the change in yield stress? Are you trying to confuse the "children" that read your paper?
heiwa said:
10. It is more likely that the energy will slip off the relevant structure (vertical column) and do no harm whatsoever. Read the complete paragraph.
STOP DODGING. You confused the terms "rupture" and "buckling" in your paper. If you had experience in the subject you wouldn't do so.
[/quote]11. No, the floors only there to transmit load on the floor to the columns. Remove the floor (and the load) and the column will still stand (thanks to spandrels and beams - and extra structure at the service floors).[/quote]
NO. See my response to 5.
heiwa said:
12. You do not know what a gravity driven collapse is, do you?. You need KE for that and it can only be provided by an intact, rigid, uniform density upper block that remains intact, rigid, with uniform density during the whole destruction of the lower structure. The upper block is the only part that can provide KE during the alleged global collapse. The lower structure does not add any extra KE to the collapse or contribute to the collapse - it is being destroyed (lack of strain energy according NIST).
The lower structure does provide additional energy to the collapse, it does this because it is a spring and it compresses. This is simple freshmen physics. Furthermore, as the upper block is damaged, it also falls and adds KE into the mix. Or are you trying to say that a section of column that weighs over 100 pounds per foot can't damage a 4" concrete slab?
heiwa said:
Actually, the upper block, intact, rigid and of uniform at start of collapse, should according to Bazant's and Seffen's theories remain INTACT after the global collapse ... on top of all rubble the upper block has produced of the lower structure. Nothing could destroy a rigid block of uniform density - not even the final impact with the ground forgetting that the rubble is there to dampen the final impact.
Stop confusing assumptions made for ease of calculation with reality. No one says the upper block ACTUALLY REMAINS INTACT except you moronic truthers searching for strawmen to validate your religion with.
I'm not some contractor, or a physicist, or a kid in college. I get paid to design buildings. You cannot go toe to toe with me with fake engineering and expect me to not call out your crap.