not all physicists "stick to atomic or sub partical props", and i imagine few physicists would agree to the claim that they could not distinguish L-Glucose and D-Glucose. i regret not knowing more chemistry, so before i start making silly naive-physicist's guesses about optical properties, perhaps you could tell us how you distinguish them empirically?
thx
1) Measure the optical rotation of a pure solution, using a polarimeter, one enantionmer will have a + value, and the other a - value, a racemic mixture will show no optical rotation.
2) Use as a food base for a particular strain of Lactobacteria. On one substrate (The L) the bacteria will not thrive, but on the other substrate (the D), the bacteria will thrive. (The bacteria only have enzymes for digesting the D-glucose, so can't use the L-glucose as a food source.
Remember, Enzymes have chirality too, so can vary in their reactivity, to the handeness of other chiral molecules.)
3) Taste. they have slightly different tastes. (that's because the receptors on our taste buds are chiral too, so there is a difference in how each enantiomer matches up with a taste receptor.)
4) Complex with a chiral Spin-coupling agent, then run throught an NMR.
The chiral spin coupling agent will cause the frequency of one enatiomers peaks to shift up slightly, and the other enantiomers to shift down slightly; So you will see the NMR of a racemic mixture, display a splitting of the peaks.
Any other physical test, not based on one of the above, will fail to tell the enantiomers apart, because in every other physical property, they are identical.
So basicaly, in order to differentiate the enantiomers of a chiral molecule, you need to resort to using another chiral molecule, to force some sort of breakdown in symetery matching. (Except The polarimiter uses a crystal, or a diffraction grid, to force light into a single plane of polarization; But this could be considered, to be just another way of forceing, a breakdown in symetery matching.)