Ok. Then define classical and non-classical. All you have done is indexed items. No other work was done.
Classical in this context means that repetition of elemens is not allowed.
Non-classical in this context means that repetition of elements is allowed.
What I did in
http://www.internationalskeptics.com/forums/showpost.php?p=11002986&postcount=951 is to use an OR logical connective between classical \ non-classical collections, which enabled me to conclude that the mutiset {1,1,1,...,2,2,2,...,3,3,3,...,...} and the set {1,2,3,...} have the same cardinality, which is |N|, if the considered structure is an infinite square matrix.
That's wonderful, but it is NOT what I said.
What you say is irrelevant to
proper infinite subsets.
Again, in order to prove that a given infinite set is
the one and only one member that is not a member of the set of all its
proper infinite subsets, one has to prove that the cardinality of the set of all
proper infinite subsets of that given infinite set, has the same cardinality of that set, and only in this case the number of rows = the number of columns (which means that we are dealing with an infinite square matrix).
It is a simple fact that each
proper infinite subset of set N has |N| members, and so is the case of any possible diagonal set across |N|
proper infinite subsets of set N (which means that our measured structure is an an infinite |N|*|N| square matrix).
In order to conclude that set N is not
the one and only one set that is not included in the infinite square matrix, one has to construct some
proper infinite subset of set N, which is different than all of the
proper infinite subsets of set N in the given infinite |N|*|N| square matrix.